Davneet Singh is a graduate from Indian Institute of Technology, Kanpur He has been teaching from the past 10 years He provides courses for Maths and Science at Teachoo 31) Determine the measure of angle A in triangle ABC, where \(\displaystyle A(1,1,8), B(4,−3,−4),\) and \(\displaystyle C(−3,1,5)\) Express your answer inSimplify (−35)(−3)(−64) (5 points)
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5 3 in cm- Find the values of tan(sin −1 3/5cot −1 3/2) inverse trigonometric functions;Calculated loga experimental log a −8 −6 −4 −50 −45 −40 −35 O2 − rmsd 1981 rr=0321 calculated loga experimental log a −8 −6 −4 −50 −45 −40 3
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Click here 👆 to get an answer to your question ️ simplify (4) {}^{ 3} (4) −3( 3) {}^{ 5} (−3) −5\binom{1}{2} {}^{ 4} ( 21 ) −4\binom{4}{9} {}^{6 On further increasing the pellet thickness to 360 µm, the volumetric capacitance at 1 mV s −1 was revealed as 460 F cm −3 and the areal performance was further improved to 23 F cm −5−3−1 ACTIONS REQUIRED 5 −3−1 5−3−2 GENERAL 5 −3−1 5−3−3 VOR ORIENTATION/VOR CROSSFIX 5 −3−2 5−3−4 GUIDANCE TO AIRPORT 5 −3−4 Section 4 Global Positioning System (GPS) 5−4−1
UTC−330 is een van de tijdzones die op het westelijk halfrond gebruikt worden, de Newfoundland Standard TimeDeze tijdzone wordt alleen in Canada gebruikt tijdens de wintertijd Gebieden in de zone van UTC−330 Gebieden op het noordelijk halfrond zijn Canada Newfoundland en het zuidoosten van LabradorThe expression √5−√3√5√3 when simplified reduces to ab√15Then a b is 15 10 5 In √5−√3√5√3 the denominator has to be rationalised for simplificationAnswer to The equation −5 (−3) = −3 (−5) illustrates the _____ property of _____
Breaking formation An endohedral cluster with Th symmetry, Sb@In8Sb123−, has been synthesized and structurally characterized The crystal structure also contains the reduced form Sb@In8Sb125−, w Click here 👆 to get an answer to your question ️ Which expression has the same value as −3 (−5)?A m a n = a m − n, a m a n = a m − n, where a ≠ 0 a ≠ 0 and m and n are integers When the exponent in the denominator is larger than the exponent in the numerator, the exponent of the quotient will be negative If the result gives us a negative exponent, we will rewrite it by using the definition of negative exponents, a − n = 1 a n
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The idea becomes clearer by considering the general series 1 − 2x 3x 2 − 4x 3 5x 4 − 6x 5 &c that arises while expanding the expression 1 ⁄ (1x) 2, which this series is Simplify (3√5−5√2)(4√53√2) (3√5−5√2)(4√53√2) = 3√5(4√53√2) − 5√2 (4√53√2) = 3√5 × 4√53√5 × 3√2 − 5√2 × 4√5−53) 5 x = 16 x 9= 16 5, y = − 5 16 9The solution is P (55, − ) b 2y 3x > x − y when the line L 1 is above the line L 2 16x < 5 2 a i ii 3x − 7 = 13 − 2x 5x = x = 4, y = 5 The lines intersect at (4, 5) iii f(x) ≤ g(x) when the f(x) is below g(x), so x ≤ 4 b i 2 b ii 8 − 5x = 14 − 3x −2x = 6 x
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